5.5+Predicting+Traffic+Jams+1011

December 14th 2010 R.K.B.

Big Idea: Many important practical and mathematical applications involve comparing quantities of one kind or another; it is important to know which method to use and how we should use them.

**5.5 Predicting Traffic Jams**
 * __// **What methods are there for comparing things?** //__

It is about 150 cars per mile. It is about 35.18 feet per vehicle. 450,237 divided by 3000= 150.079 cars per mile. 5280 multiplied by 3000= 15,840,000 divided by 450237= 35.18 feet per car.
 * A: The city of Ole has 450,237 registered vehicles for 3000 miles of road. What is the traffic density of Ole? Calculate the number of vehicles per miles of road and the number of feet of road per vehicle.**


 * B) The city of Driftwood Bay Has 396 registered vehicles for 10 miles of road. What is tHe traffic density of Driftwood Bay? Calculate tHe number of veHicles per mile of road and tHe number of feet per vehicle.**

The traffic density of Driftwood Bay is 39.6 vpm The number of feet per vehicle is 133 fpv

Hong Kong because it has 418 cars per mile of road, and that's the most so it has the highest traffic density. Driftwood Bay is the least likely because it only has 40 cars per mile and that's the least so it has the lowest traffic density.
 * C: Which one of the three cities- Hong Kong, Ole, or Driftwood Bay- do you think is most likely to have traffic jams? Explain your answer**.
 * D: Which one of the three cities is least likely to have traffic jams? Explain your answer.**

1: Other than traffic density, what factors might affect the likelihood of traffic jams:** It could be rush hour, or some big events, or car accidents. Those could all affect the traffic.
 * Follow Up:


 * 2) A typical four passenger car is about 13 feet long. What would Happen if this situation keeps getting worse?**

The traffic density would keep getting worse and worse.